When vec A cdot vec B = - |A||B|,then | vedclass

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(C) The dot product of two vectors is defined as $\vec A \cdot \vec B = |A||B| \cos 	heta$,where $	heta$ is the angle between the vectors.Given that

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$\vec A$ and $\vec B$ act in the opposite direction

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(C) The dot product of two vectors is defined as $\vec A \cdot \vec B = |A||B| \cos 	heta$,where $	heta$ is the angle between the vectors.Given that $\vec A \cdot \vec B = - |A||B|$,we can equate the two expressions:$|A||B| \cos 	heta = - |A||B|$Dividing both sides by $|A||B|$ (assuming non-zero vectors),we get:$\cos 	heta = - 1$This implies that $	heta = 180^\circ$.Therefore,the vectors $\vec A$ and $\vec B$ act in the opposite direction.

Column $-I$	Column $-II$
$(1)$ Angular momentum	$(a)$ Scalar
$(2)$ Potential energy	$(b)$ Vector
	$(c)$ Unit vector

When $\vec A \cdot \vec B = - |A||B|$,then

Similar Questions

If $\vec{A} + \vec{B} = \vec{C}$ and $|\vec{A}| + |\vec{B}| = |\vec{C}|$,what can be said about the direction of these vectors?

Match Column $-I$ with Column $-II$.

Column $-I$ Column $-II$

$(1)$ Angular momentum $(a)$ Scalar

$(2)$ Potential energy $(b)$ Vector

$(c)$ Unit vector

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If $|\vec A + \vec B| = |\vec A| + |\vec B|$,then the angle between $\vec A$ and $\vec B$ will be ....... $^o$.

If $\vec{A} + \vec{B} = \vec{C}$ and $|\vec{A}| = |\vec{B}| = |\vec{C}|$,then the angle between $\vec{A}$ and $\vec{B}$ is ....... $^o$.

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