Let S=left[-pi, frac{pi}{2}right)-left{-frac{ | vedclass

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Question

$	an 	heta+\sqrt{5} 	an 2 	heta 	an 	heta=\sqrt{5}-	an 2 	heta$ $	an 3 	heta=\sqrt{5}$

$	heta=\frac{ n \pi}{3}+\frac{\alpha}{3} ; \quad

Vedclass · Accepted Answer

$5$

Vedclass · Answer

$	an 	heta+\sqrt{5} 	an 2 	heta 	an 	heta=\sqrt{5}-	an 2 	heta$ $	an 3 	heta=\sqrt{5}$

$	heta=\frac{ n \pi}{3}+\frac{\alpha}{3} ; \quad 	an \alpha=\sqrt{5}$

Five solution

Let $S=\left[-\pi, \frac{\pi}{2}\right)-\left\{-\frac{\pi}{2},-\frac{\pi}{4},-\frac{3 \pi}{4}, \frac{\pi}{4}\right\}$. Then the number of elements in the set $=\{\theta \in S : \tan \theta(1+\sqrt{5} \tan (2 \theta))=\sqrt{5}-\tan (2 \theta)\}$ is $...$

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