Let $p , q , r$ be three logical statements. Consider the compound statements $S _{1}:((\sim p ) \vee q ) \vee((\sim p ) \vee r ) \text { and }$ and $S _{2}: p \rightarrow( q \vee r )$ Then, which of the following is NOT true$?$
If $S_{2}$ is True, then $S_{1}$ is True
If $S_{2}$ is False, then $S_{1}$ is False
If $S_{2}$ is False, then $S_{1}$ is True
If $S_{1}$ is False, then $S_{2}$ is False
Which of the following is the inverse of the proposition : “If a number is a prime then it is odd.”
$(p\rightarrow q) \leftrightarrow (q \vee ~ p)$ is
The negation of the statement $''96$ is divisible by $2$ and $3''$ is
$\sim (p \Rightarrow q) \Leftrightarrow \sim p\; \vee \sim q$ is
$\left( { \sim \left( {p \vee q} \right)} \right) \vee \left( { \sim p \wedge q} \right)$ is logically equivalent to