The negation of the statement $''96$ is divisible by $2$ and $3''$ is
The negation of the statement $''96$ is divisible by $2$ and $3''$ is
- A
$96$ is not divisible by $2$ and $3$
- B
$96$ is not divisible by $3$ or $96$ is not divisible by $2$
- C
$96$ is divisible by $2$ or $96$ is divisible by $3$
- D
none of these
Similar Questions
Consider
Statement $-1 :$$\left( {p \wedge \sim q} \right) \wedge \left( { \sim p \wedge q} \right)$ is a fallacy.
Statement $-2 :$$(p \rightarrow q) \leftrightarrow ( \sim q \rightarrow \sim p )$ is a tautology.
Consider
Statement $-1 :$$\left( {p \wedge \sim q} \right) \wedge \left( { \sim p \wedge q} \right)$ is a fallacy.
Statement $-2 :$$(p \rightarrow q) \leftrightarrow ( \sim q \rightarrow \sim p )$ is a tautology.
- [JEE MAIN 2013]
Statement$-I :$ $\sim (p\leftrightarrow q)$ is equivalent to $(p\wedge \sim q)\vee \sim (p\vee \sim q) .$
Statement$-II :$ $p\rightarrow (p\rightarrow q)$ is a tautology.
Statement$-I :$ $\sim (p\leftrightarrow q)$ is equivalent to $(p\wedge \sim q)\vee \sim (p\vee \sim q) .$
Statement$-II :$ $p\rightarrow (p\rightarrow q)$ is a tautology.
Which of the following is true
Which of the following is true
Which one of the following is a tautology ?
Which one of the following is a tautology ?
- [JEE MAIN 2020]
If $\left( {p \wedge \sim q} \right) \wedge \left( {p \wedge r} \right) \to \sim p \vee q$ is false, then the truth values of $p, q$ and $r$ are respectively
If $\left( {p \wedge \sim q} \right) \wedge \left( {p \wedge r} \right) \to \sim p \vee q$ is false, then the truth values of $p, q$ and $r$ are respectively
- [JEE MAIN 2018]