Let S be the set of all real values of k for | vedclass

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Question

The system of linear equations is:

$x+y+z=2$

$2x+y-z=3$

$3x+2y+kz=4$

As, system as unique solution.

So, $\begin{array}{*{20}{c}}

Vedclass · Accepted Answer

equal to $R- \{0\}$

Vedclass · Answer

The system of linear equations is:

$x+y+z=2$

$2x+y-z=3$

$3x+2y+kz=4$

As, system as unique solution.

So, $\begin{array}{*{20}{c}}
1&1&1\
2&1&{ - 1}\
3&2&k
\end{array} 
e 0$

$ \Rightarrow k + 2 - \left( {2k + 3} ight) + 1 
e 0$

$ \Rightarrow k 
e 0$

Hence, $k \in R - \left\{ 0 ight\} \equiv S$

Let $S$ be the set of all real values of $k$ for which the system oflinear equations $x +y + z = 2$ ; $2x +y - z = 3$ ; $3x + 2y + kz = 4$ has a unique solution. Then $S$ is

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