It is required to seat $5$ men and $4$ women in a row so that the women occupy the even places. How many such arrangements are possible?
It is required to seat $5$ men and $4$ women in a row so that the women occupy the even places. How many such arrangements are possible?
$4$ men and $4$ women are to be seated in a row such that the women occupy the even places.
The $5$ men can be seated in $5 !$ Ways. For each arrangement, the $4$ women can be seated only at the cross marked places (so that women occupy the even places).
Therefore, then women can be seated in $4!$ ways.
Thus, possible number of arrangements $=4 \times 5 !=24 \times 120=2880$
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