Ten persons,amongst whom are $A, B$ and $C$,are to speak at a function. The number of ways in which it can be done if $A$ wants to speak before $B$ and $B$ wants to speak before $C$ is:

  • A
    $\frac{10!}{6}$
  • B
    $3! \times 7!$
  • C
    $^{10}P_3 \times 7!$
  • D
    None of these

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