If (1 + tan theta )(1 + tan phi ) = 2, t | vedclass

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Question

(b) $(1 + 	an 	heta )\,\,(1 + 	an \phi ) = 2 $

$\Rightarrow \frac{{	an 	heta + 	an \phi }}{{1 - 	an 	heta 	an \phi }} = 1$&

Vedclass · Accepted Answer

${45}$

Vedclass · Answer

(b) $(1 + 	an 	heta )\,\,(1 + 	an \phi ) = 2 $

$\Rightarrow \frac{{	an 	heta + 	an \phi }}{{1 - 	an 	heta 	an \phi }} = 1$ 

$ \Rightarrow $ $	an (	heta + \phi ) = 1$ 

$ \Rightarrow $ $	heta + \phi = \frac{\pi }{4} =  45^\circ$.

If $(1 + \tan \theta )(1 + \tan \phi ) = 2$, then $\theta + \phi =$ ....$^o$

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