The solution of the equation cos^2 theta + si | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) Given equation: $\cos^2 	heta + \sin 	heta + 1 = 0$Using the identity $\cos^2 	heta = 1 - \sin^2 	heta$,we get:$1 - \sin^2 	heta + \sin 	het

Vedclass · Accepted Answer

$\left( \frac{5\pi}{4}, \frac{7\pi}{4} \right)$

Vedclass · Answer

(D) Given equation: $\cos^2 	heta + \sin 	heta + 1 = 0$Using the identity $\cos^2 	heta = 1 - \sin^2 	heta$,we get:$1 - \sin^2 	heta + \sin 	heta + 1 = 0$Rearranging the terms:$-\sin^2 	heta + \sin 	heta + 2 = 0$Multiplying by $-1$:$\sin^2 	heta - \sin 	heta - 2 = 0$Factoring the quadratic equation:$(\sin 	heta - 2)(\sin 	heta + 1) = 0$Since $\sin 	heta = 2$ is impossible (as $-1 \le \sin 	heta \le 1$),we must have:$\sin 	heta = -1$For $\sin 	heta = -1$,the general solution is $	heta = 2n\pi + \frac{3\pi}{2}$.For $n=0$,$	heta = \frac{3\pi}{2}$.Since $\frac{5\pi}{4} < \frac{3\pi}{2} < \frac{7\pi}{4}$,the solution lies in the interval $\left( \frac{5\pi}{4}, \frac{7\pi}{4} ight)$.

The solution of the equation $\cos^2 \theta + \sin \theta + 1 = 0$ lies in the interval

Similar Questions

Sprain is caused due to stretching of

In the given circuit,find the equivalent resistance between points $a$ and the combination of $b$ and $c$ (where $b$ and $c$ are connected together).

$A$ thin hollow sphere of mass $m$ is completely filled with a liquid of mass $m$. When the sphere rolls with a velocity $v$,the kinetic energy of the system is (neglect friction).

The output characteristics of an $n-p-n$ transistor represent,($I_C=$ collector current,$V_{C E}=$ potential difference between collector and emitter,$I_B=$ base current,$V_{B B}=$ voltage given to base,$V_{B E}=$ the potential difference between base and emitter)

Which of the following has the highest electropositive character?

Vedclass Test Series

Exam Paper Generator

Online Exam Module