(C) Given that $\sin \theta + \text{cosec} \theta = 2$. Squaring both sides,we get: $(\sin \theta + \text{cosec} \theta)^2 = 2^2$ $\sin^2 \theta + \te

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(C) Given that $\sin \theta + \text{cosec} \theta = 2$. Squaring both sides,we get: $(\sin \theta + \text{cosec} \theta)^2 = 2^2$ $\sin^2 \theta + \text{cosec}^2 \theta + 2 \sin \theta \text{cosec} \theta = 4$ Since $\sin \theta \text{cosec} \theta = 1$,the equation becomes: $\sin^2 \theta + \text{cosec}^2 \theta + 2(1) = 4$ $\sin^2 \theta + \text{cosec}^2 \theta = 4 - 2 = 2$ Thus,the correct option is $C$.

Class 11 Mathematics Trigonometrical Ratios, Functions and Identities Mix Examples-Trigonometrical Ratios, Functions and Identities

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If $\sin \theta + \text{cosec} \theta = 2$,then $\sin^2 \theta + \text{cosec}^2 \theta = $

A
$1$
B
$4$
C
$2$
D
None of these

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If $\sin \theta + \text{cosec} \theta = 2$,then $\sin^2 \theta + \text{cosec}^2 \theta = $

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