frac{{sin theta }}{{1 - cot theta }} + frac{{ | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(d) $\frac{{\sin 	heta }}{{1 - \cot 	heta }} + \frac{{\cos 	heta }}{{1 - 	an 	heta }}$

$ = \frac{{\sin 	heta \,.\,\sin 	heta }}{{\,\sin 	he

Vedclass · Accepted Answer

$\cos 	heta + \sin 	heta $

Vedclass · Answer

(d) $\frac{{\sin 	heta }}{{1 - \cot 	heta }} + \frac{{\cos 	heta }}{{1 - 	an 	heta }}$

$ = \frac{{\sin 	heta \,.\,\sin 	heta }}{{\,\sin 	heta - \cos 	heta }} + \frac{{\cos 	heta \,.\cos 	heta }}{{\cos 	heta - \sin 	heta }}$

$ = \frac{{({{\cos }^2}	heta - {{\sin }^2}	heta )}}{{(\cos 	heta - \sin 	heta )}} = \cos 	heta + \sin 	heta $.

$\frac{{\sin \theta }}{{1 - \cot \theta }} + \frac{{\cos \theta }}{{1 - \tan \theta }} = $

Similar Questions

$\cot x - \tan x = $

Find the value of $\sin 15^{\circ}$

If $\sin (\alpha - \beta ) = \frac{1}{2}$ and $\cos (\alpha + \beta ) = \frac{1}{2},$ where $\alpha $ and $\beta $ are positive acute angles, then

If $A + B + C = \pi $ and $\cos A = \cos B\,\cos C,$ then $\tan B\,\,\tan C$ is equal to

$(m + 2)\sin \theta + (2m - 1)\cos \theta = 2m + 1,$ if