The value of 2({sin ^6}theta + {cos ^6}theta | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(b) ${({\sin ^2}	heta + {\cos ^2}	heta )^3} = {(1)^3}$

$ \Rightarrow \,\,{\sin ^6}	heta + {\cos ^6}	heta + 3\,{\sin ^2}	heta \,{\cos ^2}	heta

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(b) ${({\sin ^2}	heta + {\cos ^2}	heta )^3} = {(1)^3}$

$ \Rightarrow \,\,{\sin ^6}	heta + {\cos ^6}	heta + 3\,{\sin ^2}	heta \,{\cos ^2}	heta = 1$

and ${\sin ^4}	heta + {\cos ^4}	heta + 2\,{\sin ^2}	heta \,{\cos ^2}	heta = 1$

Both gives, $2\,\,({\sin ^6}	heta + {\cos ^6}	heta ) - 3\,({\sin ^4}	heta + {\cos ^4}	heta ) + 1 = 0$.

The value of $2({\sin ^6}\theta + {\cos ^6}\theta ) - 3({\sin ^4}\theta + {\cos ^4}\theta ) + 1$ is

Similar Questions

$tan\,\, 20^o + tan\,\, 40^o + \sqrt 3\,\, tan\,\, 20^o tan\,\, 40^o$ is equal to

The value of $k$, for which ${(\cos x + \sin x)^2} + k\,\sin x\cos x - 1 = 0$ is an identity, is

If $\sin x + {\sin ^2}x = 1$, then the value of ${\cos ^{12}}x + 3{\cos ^{10}}x + 3{\cos ^8}x + {\cos ^6}x - 2$ is equal to

$\cot x - \tan x = $

Find the value of the trigonometric function $\tan \frac{19 \pi}{3}$.