If $\sin x+\sin ^2 x=1, x \in\left(0, \frac{\pi}{2}\right)$, then $\left(\cos ^{12} x+\tan ^{12} x\right)+3\left(\cos ^{10} x+\tan ^{10} x+\cos ^8 x+\tan ^8 x\right)$ $+\left(\cos ^6 x+\tan ^6 x\right)$ is equal to

  • [JEE MAIN 2025]
  • A
    $4$
  • B
    $3$
  • C
    $2$
  • D
    $1$

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