If $\sin \theta = \frac{{24}}{{25}}$ and $\theta $ lies in the second quadrant, then $\sec \theta + \tan \theta = $

  • A

    $-3$

  • B

    $-5$

  • C

    $-7$

  • D

    $-9$

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The equation ${\sec ^2}\theta = \frac{{4xy}}{{{{(x + y)}^2}}}$ is only possible when

  • [IIT 1966]

If $\theta $ and $\phi $ are angles in the $1^{st}$ quadrant such that $\tan \theta = 1/7$ and $\sin \phi = 1/\sqrt {10} $.Then

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