If {a^x} = bc,{b^y} = ca,,{c^z} = ab, then xy | vedclass

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Question

(d) ${a^x}.{b^y}.{c^z} = bc.ca.ab = {a^2}{b^2}{c^2}$

$ \Rightarrow $${a^{x - 2}}{b^{y - 2}}{c^{z - 2}} = 1 = {a^0}{b^0}{c^0}$

$	herefore x = y

Vedclass · Accepted Answer

$x + y + z + 2$

Vedclass · Answer

(d) ${a^x}.{b^y}.{c^z} = bc.ca.ab = {a^2}{b^2}{c^2}$

$ \Rightarrow $${a^{x - 2}}{b^{y - 2}}{c^{z - 2}} = 1 = {a^0}{b^0}{c^0}$

$	herefore x = y = z = 2$

$	herefore xyz = {2^3} = 8 = x + y + z + 2$.

If ${a^x} = bc,{b^y} = ca,\,{c^z} = ab,$ then $xyz$=

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