If log_{5} a cdot log_{a} x = 2,then x is equ | vedclass

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(C) Given the equation: $\log_{5} a \cdot \log_{a} x = 2$ Using the change of base formula $\log_{b} a = \frac{\log_{k} a}{\log_{k} b}$,we can write:

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$25$

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(C) Given the equation: $\log_{5} a \cdot \log_{a} x = 2$ Using the change of base formula $\log_{b} a = \frac{\log_{k} a}{\log_{k} b}$,we can write: $\left( \frac{\log x}{\log a} \right) \cdot \left( \frac{\log a}{\log 5} \right) = 2$ $\frac{\log x}{\log 5} = 2$ Applying the base change property in reverse: $\log_{5} x = 2$ Converting to exponential form: $x = 5^{2} = 25$

If $\log_{5} a \cdot \log_{a} x = 2$,then $x$ is equal to

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