Find the value of x^{3}+y^{3}-12xy+64,when x+ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Given expression: $x^{3}+y^{3}-12xy+64$.We know the algebraic identity: $a^{3}+b^{3}+c^{3}-3abc = (a+b+c)(a^{2}+b^{2}+c^{2}-ab-bc-ca)$.Here,let $a

Vedclass · Accepted Answer

$0$

Vedclass · Answer

(B) Given expression: $x^{3}+y^{3}-12xy+64$.We know the algebraic identity: $a^{3}+b^{3}+c^{3}-3abc = (a+b+c)(a^{2}+b^{2}+c^{2}-ab-bc-ca)$.Here,let $a=x$,$b=y$,and $c=4$.Then the expression becomes $x^{3}+y^{3}+4^{3}-3(x)(y)(4) = x^{3}+y^{3}+64-12xy$.Substituting $a+b+c = x+y+4$ into the identity:Since $x+y = -4$,we have $x+y+4 = -4+4 = 0$.Therefore,$x^{3}+y^{3}-12xy+64 = (0)(x^{2}+y^{2}+16-xy-4y-4x) = 0$.

Find the value of $x^{3}+y^{3}-12xy+64$,when $x+y=-4$.

Similar Questions

Expand $(x+3)(x+8)$.

Factorise $169 x^{2}-625$.

On dividing $x^{3} + ax^{2} + 19x + 20$ by $(x + 3)$,if the remainder is $a$,then find the value of $a$.

Find the quotient and the remainder when $x^{3}+x^{2}-10x+8$ is divided by $x+3$.

Factorise the following quadratic polynomial by splitting the middle term: $12x^2 + 23x + 5$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module