Verify whether $3$ and $5$ are zeros of the polynomial $x^{2}-x-6$ or not.
Verify whether $3$ and $5$ are zeros of the polynomial $x^{2}-x-6$ or not.
Let, $p(x)=x^{2}-x-6$
$\therefore p(3)=(3)^{2}-3-6=9-9=0$
Hence, $3$ is a zero of $p(x)=x^{2}-x-6$
$p(x)=x^{2}-x-6$
$\therefore p(5)=(5)^{2}-5-6=25-11=14$
But $14 \neq 0$
Hence, $5$ is not a zero of $p(x)=x^{2}-x-6$
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