Factorise the following:4 x^{2}+20 x+25 | vedclass

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(A) We have the expression $4 x^{2}+20 x+25$.This can be written in the form $a^{2}+2 a b+b^{2}$ as follows:$4 x^{2}+20 x+25 = (2 x)^{2}+2(2 x)(5)+(5)

Vedclass · Accepted Answer

$(2x+5)(2x+5)$

Vedclass · Answer

(A) We have the expression $4 x^{2}+20 x+25$.This can be written in the form $a^{2}+2 a b+b^{2}$ as follows:$4 x^{2}+20 x+25 = (2 x)^{2}+2(2 x)(5)+(5)^{2}$Using the algebraic identity $a^{2}+2 a b+b^{2}=(a+b)^{2}$,where $a = 2x$ and $b = 5$,we get:$(2 x+5)^{2}$Thus,the factors are $(2 x+5)(2 x+5)$.

Factorise the following:
$4 x^{2}+20 x+25$

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Factorise the following:$4 x^{2}+20 x+25$