(A) According to the Factor Theorem,$(x-1)$ is a factor of $p(x)$ if $p(1) = 0$.Substitute $x = 1$ into the polynomial:$p(1) = (1)^{3} - 7(1)^{2} + 14

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(A) According to the Factor Theorem,$(x-1)$ is a factor of $p(x)$ if $p(1) = 0$.Substitute $x = 1$ into the polynomial:$p(1) = (1)^{3} - 7(1)^{2} + 14(1) - 8$$p(1) = 1 - 7 + 14 - 8$$p(1) = 15 - 15 = 0$Since $p(1) = 0$,$(x-1)$ is a factor of the given polynomial.

Class 9 Mathematics Polynomials Mix Examples - Polynomials

Medium

Check whether $(x-1)$ is a factor of the polynomial $p(x) = x^{3}-7x^{2}+14x-8$.

A
Yes
B
No
C
Cannot be determined
D
None of these

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Check whether $(x-1)$ is a factor of the polynomial $p(x) = x^{3}-7x^{2}+14x-8$.

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The degree of the zero polynomial is

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Find the following product:
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