$\cos \left(-1710^{\circ}\right)$ નું મૂલ્ય શોધો.
We know that values of cos $x$ repeats after an interval of $2 \pi$ or $360^{\circ} .$
Therefore, $\cos \left(-1710^{\circ}\right)=\cos \left(-1710^{\circ}+5 \times 360^{\circ}\right)$
$=\cos \left(-1710^{\circ}+1800^{\circ}\right)=\cos 90^{\circ}=0$
આપેલ પૈકી ક્યો સંબધ શક્ય છે ?
$\sin \left( {\frac{\pi }{{10}}} \right)\sin \left( {\frac{{3\pi }}{{10}}} \right) = $
રેડિયન માપ શોધો : $240^{\circ}$
જો $\alpha = 22^\circ 30' $ તો $(1 + \cos \alpha )(1 + \cos 3\alpha )$ $(1 + \cos 5\alpha )(1 + \cos 7\alpha )$ = . . .. .
$2({\sin ^6}\theta + {\cos ^6}\theta ) - 3({\sin ^4}\theta + {\cos ^4}\theta ) + 1 =$