$\cos \left(-1710^{\circ}\right)$ નું મૂલ્ય શોધો.
$\cos \left(-1710^{\circ}\right)$ નું મૂલ્ય શોધો.
We know that values of cos $x$ repeats after an interval of $2 \pi$ or $360^{\circ} .$
Therefore, $\cos \left(-1710^{\circ}\right)=\cos \left(-1710^{\circ}+5 \times 360^{\circ}\right)$
$=\cos \left(-1710^{\circ}+1800^{\circ}\right)=\cos 90^{\circ}=0$
Similar Questions
સમીકરણ ${(a + b)^2} = 4ab\,\,{\sin ^2}\theta $ તોજ શક્ય છે જો . . . .
સમીકરણ ${(a + b)^2} = 4ab\,\,{\sin ^2}\theta $ તોજ શક્ય છે જો . . . .
જો ${\tan ^2}\alpha {\tan ^2}\beta + {\tan ^2}\beta {\tan ^2}\gamma + {\tan ^2}\gamma {\tan ^2}\alpha $ $ + 2{\tan ^2}\alpha {\tan ^2}\beta {\tan ^2}\gamma = 1,$ તો ${\sin ^2}\alpha + {\sin ^2}\beta + {\sin ^2}\gamma =.........$
જો ${\tan ^2}\alpha {\tan ^2}\beta + {\tan ^2}\beta {\tan ^2}\gamma + {\tan ^2}\gamma {\tan ^2}\alpha $ $ + 2{\tan ^2}\alpha {\tan ^2}\beta {\tan ^2}\gamma = 1,$ તો ${\sin ^2}\alpha + {\sin ^2}\beta + {\sin ^2}\gamma =.........$
જો $\tan \theta = \frac{{ - 4}}{3},$ તો $\sin \theta = $
જો $\tan \theta = \frac{{ - 4}}{3},$ તો $\sin \theta = $
- [IIT 1979]
જો $x{\sin ^3}\alpha + y{\cos ^3}\alpha = \sin \alpha \cos \alpha $ અને $x\sin \alpha - y\cos \alpha = 0,$ તો ${x^2} + {y^2} = $
જો $x{\sin ^3}\alpha + y{\cos ^3}\alpha = \sin \alpha \cos \alpha $ અને $x\sin \alpha - y\cos \alpha = 0,$ તો ${x^2} + {y^2} = $
જો $\sin x + {\sin ^2}x = 1,$ તો ${\cos ^8}x + 2{\cos ^6}x + {\cos ^4}x = $
જો $\sin x + {\sin ^2}x = 1,$ તો ${\cos ^8}x + 2{\cos ^6}x + {\cos ^4}x = $