If sin {theta _1} + sin {theta _2} + sin {the | vedclass

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(d) $\sin {	heta _1} + \sin {	heta _2} + \sin {	heta _3} = 3$ 

$ \Rightarrow \sin {	heta _1} = \sin {	heta _2} = \sin {	heta _3} = 1$,&n

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(d) $\sin {	heta _1} + \sin {	heta _2} + \sin {	heta _3} = 3$ 

$ \Rightarrow \sin {	heta _1} = \sin {	heta _2} = \sin {	heta _3} = 1$,       $( \because  - 1 \le \sin x \le 1)$ 

$ \Rightarrow {	heta _1} = {	heta _2} = {	heta _3} = \frac{\pi }{2} $

$\Rightarrow \cos {	heta _1} + \cos {	heta _2} + \cos {	heta _3} = 0$.

If $\sin {\theta _1} + \sin {\theta _2} + \sin {\theta _3} = 3,$ then $\cos {\theta _1} + \cos {\theta _2} + \cos {\theta _3} = $

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