Find out the following in the electric circuit given in Figure.
$(a)$ Effective resistance of two $8\,\Omega $ resistors in the combination
$(b) $ Current flowing through $4\,\Omega $ resistor
$(c)$ Potential difference across $4\,\Omega $ resistance
$(d)$ Power dissipated in $4\,\Omega $ resistor
$(e)$ Difference in ammeter readings, if any.
$(a)$ $4\, \Omega .$
$R=R_{1} R_{2} /\left(R_{1}+R_{2}\right)=\left(\frac{8 \times 8}{8+8}\right)=4\, \Omega$
$(b)$ $1\, A$.
$I=V / R=8 /(4)+\left(\frac{8 \times 8}{8+8}\right)=8 / 8=1\, A$
$(c)$ $4 \,V .$
$V=I R=14=4 \,V$
$(d) $ $4 \,W$.
$P=P R=1^{2} \quad 4=4\, W$
$(e)$ No difference.
Same current flows through each element in a series circuit.
Why is an ammeter likely to be burnt, if you connect it in parallel ?
State Ohm's law.
Two electric lamps of $100\, W$ and $25\, W$ respectively are joined in parallel to a supply of $200\, V$. Calculate the total current flowing through the circuit.
The rating of an electric heater is $1100\, W , 220\, V$. Calculate its resistance when it operates at $220\, V$. Also, calculate the energy consumed in $k W h$ in the month of November, if the heater is used daily for four hours at the rated voltage.
Define one ampere.