The rating of an electric heater is $1100\, W , 220\, V$. Calculate its resistance when it operates at $220\, V$. Also, calculate the energy consumed in $k W h$ in the month of November, if the heater is used daily for four hours at the rated voltage.

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Given $P =1100 W , V =220 V$

$t=4 \times 30=120$ hour

Using the expression

$R =\frac{ V ^{2}}{ P },$ we have

$R =\frac{(220)^{2}}{1100}=44 \Omega$

Energy consumed

$E=P \times t=1100 \times 120$

$=132000 Wh$

$=132 kWh$

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