The rating of an electric heater is $1100 \ W, 220 \ V$. Calculate its resistance when it operates at $220 \ V$. Also,calculate the energy consumed in $kWh$ in the month of November,if the heater is used daily for four hours at the rated voltage.

(N/A) Given: Power $P = 1100 \ W$,Voltage $V = 220 \ V$.
$1$. Calculation of Resistance:
Using the formula $R = \frac{V^2}{P}$,we have:
$R = \frac{(220)^2}{1100} = \frac{48400}{1100} = 44 \ \Omega$.
$2$. Calculation of Energy Consumed:
The month of November has $30$ days.
Total time $t = 4 \ \text{hours/day} \times 30 \ \text{days} = 120 \ \text{hours}$.
Energy $E = P \times t = 1100 \ \text{W} \times 120 \ \text{h} = 132000 \ \text{Wh}$.
To convert into $kWh$,divide by $1000$:
$E = \frac{132000}{1000} = 132 \ kWh$.