The rating of an electric heater is $1100\, W , 220\, V$. Calculate its resistance when it operates at $220\, V$. Also, calculate the energy consumed in $k W h$ in the month of November, if the heater is used daily for four hours at the rated voltage.
Given $P =1100 W , V =220 V$
$t=4 \times 30=120$ hour
Using the expression
$R =\frac{ V ^{2}}{ P },$ we have
$R =\frac{(220)^{2}}{1100}=44 \Omega$
Energy consumed
$E=P \times t=1100 \times 120$
$=132000 Wh$
$=132 kWh$
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