Why is an ammeter likely to be burnt if you connect it in parallel?

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(N/A) An ammeter is designed to have a very low resistance so that it can measure current without significantly altering the circuit. When connected in parallel,the potential difference across the ammeter is the same as the potential difference across the circuit components. Due to its extremely low resistance,a very large amount of current flows through the ammeter according to Ohm's Law $(I = V/R)$. This excessive current generates significant heat $(H = I^2Rt)$,which causes the internal components of the ammeter to overheat and burn out.

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Calculate the number of electrons constituting one coulomb of charge. (Charge on one electron $= 1.6 \times 10^{-19} \text{ C}$)

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