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At a place, if the earth's horizontal and vertical components of magnetic fields are equal, then the angle of dip will be.......$^o$

The vertical component of the earth's magnetic field is $6 \times 10^{-5} T$ at any place where the angle of dip is $37^{\circ}$. The earth's resultant magnetic field at that place will be $\left(\right.$ Given $\left.\tan 37^{\circ}=\frac{3}{4}\right)$

Angle of dip is $90^o$ at

The earth's magnetic field at a certain place has a horizontal component $0.3$ $Gauss$ and the total strength $0.5$ $Gauss$. The angle of dip is

Two bar magnets oscillate in a horizontal plane in earth's magnetic field with time periods of $3\,s$ and $4\,s$ respectively. If their moments of inertia are in the ratio of $3: 2$ then the ratio of their magnetic moments will e.