The vertical component of the earth's magneti | vedclass

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Question

(D) The vertical component of the earth's magnetic field $(B_V)$ is related to the resultant magnetic field $(B)$ and the angle of dip $(\delta)$ by t

Vedclass · Accepted Answer

$1 	imes 10^{-4} 	ext{ T}$

Vedclass · Answer

(D) The vertical component of the earth's magnetic field $(B_V)$ is related to the resultant magnetic field $(B)$ and the angle of dip $(\delta)$ by the formula: $B_V = B \sin \delta$ Given that $B_V = 6 	imes 10^{-5} 	ext{ T}$ and $\delta = 37^{\circ}$. Since $	an 37^{\circ} = \frac{3}{4}$,we can form a right-angled triangle with opposite side $3$ and adjacent side $4$. The hypotenuse is $\sqrt{3^2 + 4^2} = 5$. Therefore,$\sin 37^{\circ} = \frac{3}{5}$. Substituting the values into the formula: $6 	imes 10^{-5} = B 	imes \frac{3}{5}$ $B = \frac{6 	imes 10^{-5} 	imes 5}{3}$ $B = 2 	imes 10^{-5} 	imes 5$ $B = 10 	imes 10^{-5} 	ext{ T} = 10^{-4} 	ext{ T}$

The vertical component of the earth's magnetic field is $6 \times 10^{-5} \text{ T}$ at a place where the angle of dip is $37^{\circ}$. The earth's resultant magnetic field at that place will be (Given $\tan 37^{\circ} = \frac{3}{4}$)

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