The angle of dip is $90^{\circ}$ at:

The north pole of the earth's magnet is near the geographical

What is magnetic declination?

The lines of force due to the Earth's horizontal component of the magnetic field are:

The dip angle in a vertical plane at an angle of $\cos^{-1} \left( \frac{1}{\sqrt{2}} \right)$ from the magnetic meridian is $60^\circ$. Find the actual dip angle at that place.

At a certain place,the horizontal component of earth's magnetic field is $\sqrt{3}$ times the vertical component. The angle of dip at that place is....$^o$