$A$ string of length $L$ and mass $M$ hangs freely from a fixed point. The velocity of transverse waves along the string at a distance $x$ from the free end is

Two strings with circular cross section and made of same material are stretched to have the same amount of tension. $A$ transverse wave is then made to pass through both the strings. The velocity of the wave in the first string having the radius of cross section $R$ is $v_1$,and that in the other string having radius of cross section $R/2$ is $v_2$. Then $\frac{v_2}{v_1} = $

$A$ string is producing transverse vibration whose equation is $y = 0.021 \sin(x + 30t)$,where $x$ and $y$ are in meters and $t$ is in seconds. If the linear density of the string is $1.3 \times 10^{-4} \ kg/m$,then the tension in the string in $N$ will be:

The equation of a transverse wave propagating on a stretched string is given by $y = 3 \sin (4x + 200t)$,where $x$ and $y$ are in metres and the time $t$ is in seconds. If the tension applied to the string is $500 \ N$,the linear density of the string is: (in $kg \ m^{-1}$)

The extension in a string obeying Hooke's law is $x$. The speed of sound in the stretched string is $v$. If the extension in the string is increased to $1.5x$,the speed of sound will be (in $,v$)

$A$ wire $PQ$ has length $4.8 \ m$ and mass $0.06 \ kg$. Another wire $QR$ has length $2.56 \ m$ and mass $0.2 \ kg$. Both wires have the same radii and are joined as a single wire. This wire is under a tension of $80 \ N$. $A$ wave pulse of amplitude $3.5 \ cm$ is sent along the wire $PQ$ from end $P$. The time taken by the wave to reach the other end of the single wire is (No power is dissipated during propagation). (in $s$)