A heavy ball of mass M is suspended from the | vedclass

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Question

$60=\sqrt{\frac{M g}{\mu}}$

$60.5=\sqrt{\frac{M\left(g^{2}+a^{2}\right)^{1 / 2}}{\mu}} \Rightarrow \frac{60.5}{60}=\sqrt{\sqrt{\frac{g^{2}+a^{2}}{g

Vedclass · Accepted Answer

$\frac{g}{{5}}$

Vedclass · Answer

$60=\sqrt{\frac{M g}{\mu}}$

$60.5=\sqrt{\frac{M\left(g^{2}+a^{2}ight)^{1 / 2}}{\mu}} \Rightarrow \frac{60.5}{60}=\sqrt{\sqrt{\frac{g^{2}+a^{2}}{g^{2}}}}$

$\left(1+\frac{0.5}{60}ight)^{4}=\frac{g^{2}+a^{2}}{g^{2}}=1+\frac{2}{60}$

$\Rightarrow g^{2}+a^{2}=g^{2}+g^{2} 	imes \frac{2}{60}$

$a=g \sqrt{\frac{2}{60}}=\frac{g}{\sqrt{30}}=\frac{g}{5.47}$

$\simeq \frac{g}{5}$

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