किसी खोखले आवेशित चालक में उसके पृष्ठ पर कोई छिद्र बनाया गया है। यह दर्शाइए कि छिद्र में विध्यूत क्षेत्र $\left(\sigma / 2 \varepsilon_{0}\right) \hat{ n }$ है, जहाँ $\hat{ n }$ अभिलंबवत दिशा में बहिर्मुखी एकांक सदिश है तथा $\sigma$ छिद्र के निकट पृष्ठीय आवेश घनत्व है

Let us consider a conductor with a cavity or a hole. Electric field inside the cavity is zero. Let $E$ is the electric field just outside the conductor, $q$ is the electric charge, $\sigma$ is the charge density and $\epsilon_{0}$ is the permittivity of free space. Charge $q=\sigma \times d s$

According to Gauss's law, flux, $\phi=E . d s=\frac{q}{\epsilon_{0}}$

$\Rightarrow E \cdot d s=\frac{\sigma \times d s}{\epsilon_{0}}$

$\therefore E =\frac{\sigma}{2 \epsilon_{0}} \hat{n}$

Therefore, the electric field just outside the conductor is $\frac{\sigma}{2 \epsilon_{0}} \hat{n} .$ This field is a superposition of field due to the cavity $E '$ and the field due to the rest of the charged conductor $E'$. These fields are equal and opposite inside the conductor and equal in magnitude and direction outside the conductor. $\therefore E '+ E '= E$

$\Rightarrow E'=\frac{ E }{2}=\frac{\sigma}{2 \epsilon_{0}} \hat{n}$

Hence, the field due to the rest of the conductor is $\frac{\sigma}{\epsilon_{0}} \hat{n}$