(C) The maximum horizontal range $R_{\max}$ of a projectile is given by the formula:$R_{\max} = \frac{u^2}{g}$where $u$ is the initial speed and $g$ i

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(C) The maximum horizontal range $R_{\max}$ of a projectile is given by the formula:$R_{\max} = \frac{u^2}{g}$where $u$ is the initial speed and $g$ is the acceleration due to gravity.Given $R_{\max} = 100 \, m$ and taking $g = 10 \, m/s^2$:$100 = \frac{u^2}{10}$$u^2 = 1000$$u = \sqrt{1000} \approx 31.62 \, m/s$Rounding to the nearest integer,we get $u = 32 \, m/s$.

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$A$ cricketer can throw a ball to a maximum horizontal distance of $100 \, m$. The speed with which he throws the ball is (to the nearest integer) (in $m/s$).

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$42$
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$32$
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$35$

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$A$ cricketer can throw a ball to a maximum horizontal distance of $100 \, m$. The speed with which he throws the ball is (to the nearest integer) (in $m/s$).

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