Two projectiles of same mass and with same ve | vedclass

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(A) The horizontal range $R$ of a projectile is given by the formula $R = \frac{u^2 \sin(2	heta)}{g}$.Given that the initial velocity $u$ is the same

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Horizontal range of projectile

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(A) The horizontal range $R$ of a projectile is given by the formula $R = \frac{u^2 \sin(2	heta)}{g}$.Given that the initial velocity $u$ is the same for both projectiles.For the first projectile,$	heta_1 = 60^o$,so $R_1 = \frac{u^2 \sin(120^o)}{g} = \frac{u^2 \sin(60^o)}{g}$.For the second projectile,$	heta_2 = 30^o$,so $R_2 = \frac{u^2 \sin(60^o)}{g}$.Since $\sin(120^o) = \sin(60^o)$,the horizontal range $R$ is the same for both angles.Angles $	heta$ and $(90^o - 	heta)$ are complementary angles,and for any pair of complementary angles,the horizontal range is identical.

Two projectiles of same mass and with same velocity are thrown at an angle $60^o$ and $30^o$ with the horizontal,then which quantity will remain same?

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