A particle is projected from ground with velocity $u$ at angle $\theta$ from horizontal. Match the following two columns.
Column $I$ | Column $II$ |
$(A)$ Average velocity between initial and final points | $(p)$ $u \sin \theta$ |
$(B)$ Change in velocity between initial and final points | $(q)$ $u \cos \theta$ |
$(C)$ Change in velocity between initial and final points | $(r)$ Zero |
$(D)$ Average velocity between initial and highest points | $(s)$ None of the above |
$( A \rightarrow q , B \rightarrow s , C \rightarrow p , D \rightarrow p )$
$( A \rightarrow s , B \rightarrow q , C \rightarrow p , D \rightarrow p )$
$( A \rightarrow q , B \rightarrow p , C \rightarrow s , D \rightarrow p )$
$( A \rightarrow s , B \rightarrow q , C \rightarrow r , D \rightarrow p )$
What is range of the projectile particle ? Give velocity of projectile particle at maximum height.
A particle is projected from a horizontal plane ($x-z$ plane) such that its velocity vector at time t is given by $\vec V = a\hat i + (b - ct)\hat j$ Its range on the horizontal plane is given by
A projectile is thrown at an angle $\theta$ such that it is just able to cross a vertical wall at its highest point as shown in the figure.The angle $\theta$ at which the projectile is thrown is given by
A bullet is fired from a cannon with velocity $500 \,m/s$. If the angle of projection is ${15^o}$ and $g = 10m/{s^2}$. Then the range is
The equation of projectile is $y = 16x\, - \,\frac{{5{x^2}}}{4}$, The horizontal range is .......... $m$