(B) The initial velocity of the ball is $u = 15 \ m/s$ and the angle of projection is $\theta = 37^o$. Taking $g = 10 \ m/s^2$,we have $\sin(37^o) \ap

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(B) The initial velocity of the ball is $u = 15 \ m/s$ and the angle of projection is $\theta = 37^o$. Taking $g = 10 \ m/s^2$,we have $\sin(37^o) \approx 0.6$.The total time of flight $T$ is given by:$T = \frac{2u \sin(\theta)}{g} = \frac{2 \times 15 \times 0.6}{10} = \frac{18}{10} = 1.8 \ s$.The man is at point $P$,which is $9 \ m$ away from the landing point $B$. To catch the ball,the man must cover this distance $d = 9 \ m$ within the time of flight $T = 1.8 \ s$.The minimum velocity $v$ required is:$v = \frac{d}{T} = \frac{9}{1.8} = 5 \ m/s$.

Class 11 Physics 3-2.Motion in Plane Mix Examples-Motion in Plane

Medium

$A$ ball is hit by a batsman at an angle of $37^o$ with an initial velocity $u = 15 \ m/s$ as shown in the figure. The man standing at $P$ is at a distance of $9 \ m$ from the point $B$ where the ball would strike the ground. What is the minimum velocity at which the man should run to catch the ball before it hits the ground? Assume the height of the man is negligible. ........ $m/s$

A
$3$
B
$5$
C
$9$
D
$12$

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3-2.Motion in Plane

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Mix Examples-Motion in Plane

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Medium

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Which of the following graphs represents the relationship between the height $(h)$ of a projectile and time $(t)$,when it is projected from the ground?

Easy

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An aircraft is flying at a height of $H$ above the ground at a constant speed $V$. What is the maximum angle subtended at a ground observation point by the aircraft's path after time $T$?

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