$A$ ball is projected with kinetic energy $E$ at an angle of $45^\circ$ to the horizontal. At the highest point during its flight,its kinetic energy will be

  • A
    Zero
  • B
    $E/2$
  • C
    $E/\sqrt{2}$
  • D
    $E$

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Similar Questions

The equation of motion of a projectile is $y = ax - bx^2$,where $a$ and $b$ are constants. Match the Column-$I$ with Column-$II$:
Column-$I$Column-$II$
$i)$ The initial velocity of projection$a)$ $\sqrt{\frac{g(1+a^2)}{2b}}$
$ii)$ The horizontal range of projectile$b)$ $\frac{a}{b}$
$iii)$ The maximum height attained by projectile$c)$ $\frac{a^2}{4b}$
$iv)$ The time of flight of projectile$d)$ $a\sqrt{\frac{2}{bg}}$

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$A$ body projected with some velocity at an angle $45^{\circ}$ with the horizontal from the origin in $XY$-plane passes through a point at $(4, 3) \ m$. Its horizontal range is (in $m$)

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