$A$ projectile is thrown with velocity $v$ making an angle $\theta$ with the vertical. It reaches a maximum height $H$. The time of flight is:

  • A
    $\sqrt{H \cos \theta / g}$
  • B
    $\sqrt{2H \cos \theta / g}$
  • C
    $\sqrt{4H / g}$
  • D
    $\sqrt{8H / g}$

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