$\mathop {\lim }\limits_{x \to 0} \frac{{x\cos x - \sin x}}{{{x^2}\sin x}} = $

  • A
    $\frac{1}{3}$
  • B
    $-\frac{1}{3}$
  • C
    $1$
  • D
    આમાંથી કોઈ નહીં

Explore More

Similar Questions

$\mathop {\lim }\limits_{x \to \infty } \frac{{{x^n}}}{{{e^x}}} = 0$ માટે

ધારો કે $f: R \rightarrow R$ એ $x=0$ આગળ વિકલનીય છે. જો $f(0)=0$ અને $f'(0)=2$ હોય,તો $\lim _{x \rightarrow 0} \frac{1}{x} [f(x)+f(2 x)+f(3 x)+\ldots+f(2015 x)]$ ની કિંમત શોધો.

$\mathop {Limit}\limits_{x \to 0} {(\cos 2x)^{3/x^2}}$ ની કિંમત . . . . . . છે.

ધારો કે $f(x) = \int_0^x (t + \sin(1 - e^t)) dt, x \in R$. તો $\lim_{x \rightarrow 0} \frac{f(x)}{x^3}$ ની કિંમત શોધો.

જો $f(5)=7$ અને $f'(5)=7$ હોય,તો $\lim_{x \rightarrow 5} \frac{x f(5)-5 f(x)}{x-5}$ ની કિંમત શોધો.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo