${({x^5})^{1/3}}{(16{x^3})^{2/3}}$${\left( {{1 \over 4}{x^{4/9}}} \right)^{ - 3/2}} = $

  • A

    ${(x/4)^3}$

  • B

    ${(4x)^3}$

  • C

    $8{x^3}$

  • D

    એકપણ નહીં

Similar Questions

સમીકરણ $\sqrt {(x + 1)} - \sqrt {(x - 1)} = \sqrt {(4x - 1)} $, $x \in R$ ને .. . .

${4 \over {1 + \sqrt 2 - \sqrt 3 }} = $

જો $x = {2^{1/3}} - {2^{ - 1/3}},$ તો $2{x^3} + 6x = $

જો ${a^x} = {b^y} = {(ab)^{xy}},$ તો $x + y = $

જો $x = {{\sqrt 5 + \sqrt 2 } \over {\sqrt 5 - \sqrt 2 }},y = {{\sqrt 5 - \sqrt 2 } \over {\sqrt 5 + \sqrt 2 }},$ તો $3{x^2} + 4xy - 3{y^2} = $