$\sum_{k=0}^{20} \left({}^{20}C_{k}\right)^{2}$ ની કિંમત શું થાય?

  • A
    ${}^{40}C_{21}$
  • B
    ${}^{40}C_{19}$
  • C
    ${}^{40}C_{20}$
  • D
    ${}^{41}C_{20}$

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ધારો કે $\binom{n}{k}$ એ ${}^{n}C_{k}$ દર્શાવે છે અને $\left[\begin{array}{c} n \\ k \end{array}\right]=\begin{cases} \binom{n}{k}, & \text{જો } 0 \leq k \leq n \\ 0, & \text{અન્યથા} \end{cases}$. જો $A_{k}=\sum_{i=0}^{9}\binom{9}{i}\left[\begin{array}{c} 12 \\ 12-k+i \end{array}\right]+\sum_{i=0}^{8}\binom{8}{i}\left[\begin{array}{c} 13 \\ 13-k+i \end{array}\right]$ અને $A_{4}-A_{3}=190p$ હોય,તો $p$ ની કિંમત શોધો:

$-{ }^{15}C_{1} 2 \cdot { }^{15}C_{2} - 3 \cdot { }^{15}C_{3} \ldots - 15 \cdot { }^{15}C_{15} { }^{14}C_{1} { }^{14}C_{3} { }^{14}C_{5} \ldots { }^{14}C_{11}$ ની કિંમત શોધો.

$\frac{{^nC_0}}{1} + \frac{{^nC_2}}{3} + \frac{{^nC_4}}{5} + \frac{{^nC_6}}{7} + \dots = $

ધારો કે $a_0, a_1, a_2, \ldots, a_n \in \mathbb{R}$ એ સમાંતર શ્રેણીમાં છે અને $C_0, C_1, C_2, \ldots, C_n$ એ દ્વિપદી સહગુણકો છે. તો $\sum_{k=0}^n a_k \cdot C_k =$

$^{4n}C_0 + ^{4n}C_4 + ^{4n}C_8 + ... + ^{4n}C_{4n}$ નું મૂલ્ય શું છે?

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