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General methods of preparation and mechanism of polymerisation Questions in English

Class 12 Chemistry · Polymers · General methods of preparation and mechanism of polymerisation

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101
EasyMCQ
The Ziegler-Natta catalyst is.....
A
$Pt/PtO_2$
B
$Al(C_2H_5)_3 + TiCl_4$
C
$K[PtCl_3(\eta^2 - C_2H_4)]$
D
$Pt/Rh$

Solution

(B) The Ziegler-Natta catalyst is a mixture of triethylaluminium $(Al(C_2H_5)_3)$ and titanium tetrachloride $(TiCl_4)$.
It is widely used in the industrial polymerization of alkenes,such as the production of high-density polyethylene $(HDPE)$.
102
MediumMCQ
Phenol is reacted with which of the following to obtain Bakelite?
A
Acetaldehyde
B
Formaldehyde
C
Baking soda
D
Formic acid

Solution

(B) Bakelite is a thermosetting polymer formed by the condensation polymerization of phenol and formaldehyde in the presence of an acid or base catalyst. The reaction is as follows: $n C_6H_5OH + n HCHO \rightarrow \text{Bakelite}$.
103
MediumMCQ
Which of the following reagents is required to obtain Bakelite from phenol?
A
$HCHO$
B
$CHCl_3 / NaOH$
C
$CCl_4 / NaOH$
D
$HCHO / H_2O$

Solution

(A) The condensation reaction of phenol with formaldehyde $(HCHO)$ in the presence of an acid or base catalyst leads to the formation of the polymer Bakelite.
104
EasyMCQ
Which of the following reactions produces Bakelite?
A
Urea with $HCHO$
B
Tetramethyl glycol with hexamethylene diisocyanate
C
Phenol and $HCHO$
D
Ethylene glycol and dimethyl terephthalate

Solution

(C) Bakelite is obtained by the polymerization of phenol and formaldehyde $(HCHO)$ in the presence of an acid or base catalyst.
This is a condensation polymerization reaction.
105
EasyMCQ
Nylon $-6$ is made from
A
Butadiene
B
Chloroprene
C
Adipic acid
D
Caprolactum

Solution

(D) Caprolactum is the monomer of nylon $-6$.
When caprolactum is heated with water at high temperature,it undergoes ring-opening polymerization to form nylon $-6$.
106
EasyMCQ
Are small molecules liberated during addition polymerization?
A
Yes
B
No
C
Sometimes
D
Only $H_2O$

Solution

(B) In addition polymerization,the simple addition of monomer units takes place without the loss of any small molecules. This is in contrast to condensation polymerization,where small molecules like $H_2O$,$HCl$,or $NH_3$ are typically eliminated.
107
MediumMCQ
The straight chain polymer is formed by
A
hydrolysis of $CH_3SiCl_3$ followed by condensation polymerisation
B
hydrolysis of $(CH_3)_4Si$ by addition polymerisation
C
hydrolysis of $(CH_3)_2SiCl_2$ followed by condensation polymerisation
D
hydrolysis of $(CH_3)_3SiCl$ followed by condensation polymerisation.

Solution

(C) The hydrolysis of dimethyl dichlorosilane,$(CH_3)_2SiCl_2$,produces a dihydroxy derivative,$(CH_3)_2Si(OH)_2$.
This dihydroxy derivative undergoes condensation polymerisation to form a straight chain silicone polymer,as shown in the reaction:
$n(CH_3)_2SiCl_2 + 2nH_2O \rightarrow n(CH_3)_2Si(OH)_2 + 2nHCl$
$n(CH_3)_2Si(OH)_2 \rightarrow -[O-Si(CH_3)_2-O]_n- + nH_2O$
108
MediumMCQ
Caprolactam is used for the manufacture of
A
teflon
B
terylene
C
nylon $6, 6$
D
nylon $6$

Solution

(D) Caprolactam is heated with water at high temperature to undergo ring-opening polymerization.
This process yields $6$-aminohexanoic acid,which upon further heating undergoes condensation polymerization to form the polymer known as nylon $6$.
Therefore,caprolactam is the monomer used for the manufacture of nylon $6$.
109
MediumMCQ
Which of the following is the monomer of neoprene?
A
$CH_2=C(Cl)-CH=CH_2$
B
$CH_2=CH-C \equiv CH$
C
$CH_2=CH-CH=CH_2$
D
$CH_2=C(CH_3)-CH=CH_2$

Solution

(A) Neoprene is a synthetic rubber produced by the polymerization of chloroprene.
The $IUPAC$ name of chloroprene is $2$-chloro-$1,3$-butadiene.
Its chemical structure is $CH_2=C(Cl)-CH=CH_2$.
110
DifficultMCQ
Which one of the following polymers is prepared by condensation polymerisation?
A
Teflon
B
Natural rubber
C
Styrene
D
Nylon $6,6$

Solution

(D) Condensation Polymerization: This is a process of polymer formation by the reaction of smaller molecules to form bigger ones,with the elimination of small molecules such as $H_{2}O$ or methanol.
For example: In the formation of $Nylon-6,6$,small molecules of hexamethylenediamine and adipic acid react,resulting in the removal of a water molecule for each condensation step between the two monomers.
111
MediumMCQ
Bakelite is obtained from phenol by reacting with
A
$CH_2(OH)_2$
B
$CH_3CHO$
C
$CH_3COCH_3$
D
$HCHO$

Solution

(D) Bakelite is a thermosetting polymer formed by the condensation polymerization of phenol and formaldehyde $(HCHO)$.
In the presence of an acid or base catalyst,phenol reacts with formaldehyde to form $o$- and $p$-hydroxymethylphenol intermediates.
These intermediates undergo further polymerization to form a linear polymer called Novolac.
Upon heating with more formaldehyde,Novolac undergoes cross-linking to form the infusible,hard,and cross-linked polymer known as Bakelite.
112
MediumMCQ
The species which can best serve as an initiator for the cationic polymerization is:
A
$LiAlH_4$
B
$HNO_3$
C
$AlCl_3$
D
$BaLi$

Solution

(C) Cationic polymerization is initiated by electrophiles or Lewis acids.
Electron-deficient species (Lewis acids) such as $AlCl_3$,$BF_3$,and $SnCl_4$ are commonly used as initiators for cationic polymerization because they can generate carbocations from the monomer.
Among the given options,$AlCl_3$ is a well-known Lewis acid.
113
DifficultMCQ
The formation of which of the following polymers involves a hydrolysis reaction?
A
Nylon $6$
B
Bakelite
C
Nylon $6, 6$
D
Terylene

Solution

(A) Nylon-$6$ is prepared by heating $\varepsilon$-caprolactam with water at a high temperature $(533-543 \ K)$.
In this process,the cyclic amide ring of $\varepsilon$-caprolactam undergoes a hydrolysis reaction to form an amino acid,which then undergoes polymerization to form Nylon-$6$.
114
DifficultMCQ
The polymer $(Q)$ produced in the following sequence is:
Cyclohexanone $\xrightarrow[{(ii)\,\,{H_2}SO_4\,,\,\Delta }]{{(i)\,\,NH_2 - OH}}\,P\,$ $\xrightarrow[{533\, - \,543\,\,K}]{{{H_2}O}}Q$
A
Nylon $-6,6$
B
Nylon $-4,6$
C
Nylon $-6$
D
Terylene

Solution

(C) $1$. The starting material is cyclohexanone.
$2$. Reaction with hydroxylamine $(NH_2OH)$ followed by acid-catalyzed rearrangement (Beckmann rearrangement) using $H_2SO_4$ and heat converts cyclohexanone into caprolactam (intermediate $P$).
$3$. Caprolactam,when heated with water at $533-543 \ K$,undergoes ring-opening polymerization to form Nylon $-6$ (polymer $Q$).
$4$. Therefore,the correct option is $C$.
115
MediumMCQ
Which of the following polymers can be formed by using the following monomer unit?
Question diagram
A
Nylon-$6, 6$
B
Nylon-$2$-nylon-$6$
C
Melamine polymer
D
Nylon-$6$

Solution

(D) The given monomer unit is caprolactam.
Caprolactam,when heated with water at high temperature,undergoes ring-opening polymerization to form Nylon-$6$.
The reaction is:
Caprolactam $\xrightarrow{H_2O, \Delta}$ Nylon-$6$.
116
MediumMCQ
If $1,3$-butadiene is polymerized by a free radical synthesis,the possible product contains which repeating units?
Question diagram
A
$(i) \& (ii)$
B
$(iii)$ only
C
$(i)$ only
D
$(i), (ii) \& (iii)$

Solution

(A) The polymerization of $1,3$-butadiene $(CH_2=CH-CH=CH_2)$ via free radical mechanism involves $1,4$-addition.
This results in the formation of polybutadiene,which can exist in two geometric isomeric forms due to the double bond in the polymer chain:
$1$. $cis$-$1,4$-polybutadiene (represented by structure $(i)$).
$2$. $trans$-$1,4$-polybutadiene (represented by structure $(ii)$).
Structure $(iii)$ represents a saturated chain which is not formed by the $1,4$-polymerization of $1,3$-butadiene.
Therefore,the possible products contain repeating units $(i)$ and $(ii)$.
117
MediumMCQ
The widely used plastic $PVC$ is a polymerization product of
A
$CH_2=CH_2$
B
$CH_2=CHCl$
C
$CHCl=CHCl$
D
$CH_2=CCl_2$

Solution

(B) $PVC$ stands for Polyvinyl chloride.
It is formed by the addition polymerization of vinyl chloride monomer,which has the chemical formula $CH_2=CHCl$.
118
MediumMCQ
The Ziegler-Natta catalyst used for polymerisation of ethene and styrene is $TiCl_4 + (C_2H_5)_3Al$. The catalysing species (active species) involved in the polymerisation is
A
$TiCl_4$
B
$TiCl_3$
C
$TiCl_2$
D
$TiCl$

Solution

(B) The Ziegler-Natta catalyst is a mixture of titanium tetrachloride $(TiCl_4)$ and an organoaluminium compound like triethylaluminium $((C_2H_5)_3Al)$.
In the reaction mechanism,$TiCl_4$ is reduced by the organoaluminium compound to form an active species containing $Ti(III)$,which is $TiCl_3$ (or an alkylated derivative thereof).
This $TiCl_3$ species acts as the active site where the monomer coordinates and undergoes insertion into the metal-carbon bond to propagate the polymer chain.
119
MediumMCQ
Neoprene rubber is obtained by the polymerization of:
A
$1, 3-$Butadiene
B
$2-$Methyl$-1, 3-$butadiene
C
$2-$Chloro$-1, 3-$butadiene
D
Styrene and butadiene

Solution

(C) Neoprene,also known as polychloroprene,is a synthetic rubber produced by the free-radical polymerization of the monomer $2-$chloro$-1, 3-$butadiene (also known as chloroprene).
The chemical reaction is:
$n \ CH_2=C(Cl)-CH=CH_2 \rightarrow -[CH_2-C(Cl)=CH-CH_2]_n-$
120
MediumMCQ
$PHBV$ is a polymer of
A
$3-$Hydroxybutanoic acid and $3-$Hydroxypentanoic acid
B
$2-$Hydroxybutanoic acid and $2-$Hydroxypentanoic acid
C
$4-$Hydroxybutanoic acid and $4-$Hydroxypentanoic acid
D
$3-$Hydroxybutanoic acid and $2-$Hydroxypentanoic acid

Solution

(A) $PHBV$ stands for Poly-$\beta$-hydroxybutyrate-co-$\beta$-hydroxyvalerate.
It is a copolymer obtained by the polymerization of $3-$hydroxybutanoic acid and $3-$hydroxypentanoic acid.
Therefore,the correct option is $A$.
121
MediumMCQ
The fibre obtained by the condensation of hexamethylene diamine and adipic acid is
A
$Dacron$
B
$Nylon$ $6,6$
C
$Rayon$
D
$Teflon$

Solution

(B) $Nylon$ $6,6$ is a polyamide fibre obtained by the condensation polymerization of hexamethylene diamine $(H_2N(CH_2)_6NH_2)$ and adipic acid $(HOOC(CH_2)_4COOH)$.
122
MediumMCQ
The monomeric units of Bakelite are:
A
$HCHO + C_6H_5OH$
B
$HCHO + \text{Melamine}$
C
$CH_2=CH-CH=CH_2 + C_6H_5CH=CH_2$
D
$HCHO + CF_2=CF_2$

Solution

(A) Bakelite is a thermosetting polymer formed by the condensation polymerization of phenol $(C_6H_5OH)$ and formaldehyde $(HCHO)$.
Therefore,the monomeric units of Bakelite are phenol and formaldehyde.
123
EasyMCQ
Orlon is a polymer of
A
Styrene
B
$CF_2=CF_2$
C
Vinyl cyanide
D
Acrolein

Solution

(C) Orlon,also known as polyacrylonitrile $(PAN)$,is a synthetic polymer formed by the polymerization of acrylonitrile (also known as vinyl cyanide).
The chemical reaction is: $n CH_2=CH(CN) \rightarrow -[CH_2-CH(CN)]_n-$.
Therefore,the monomer of Orlon is vinyl cyanide.
124
EasyMCQ
During the formation of bakelite,which initial linear product is formed?
A
Melamine
B
$PHBV$
C
Novolac
D
Acrylonitrile

Solution

(C) Bakelite is a thermosetting polymer formed by the condensation reaction of phenol and formaldehyde in the presence of an acid or base catalyst.
In the initial stage,the reaction produces a linear polymer known as $Novolac$.
$Novolac$ is a linear chain of phenol units linked by methylene bridges.
Upon further heating with more formaldehyde,$Novolac$ undergoes cross-linking to form the infusible,hard,and rigid solid known as Bakelite.
125
AdvancedMCQ
The following structure represents a subunit of a hydrocarbon polymer that may be prepared by a radical polymerization method. Identify the monomer that has been polymerized to make this polymer chain.
Question diagram
A
$1$-Hexene
B
$n$-Hexane
C
$1$-Pentene
D
$2$-Methyl-$1$-pentene

Solution

(A) The given polymer structure is a poly($1$-alkene). By examining the repeating unit,we can identify the monomer. The backbone consists of a $2$-carbon chain with a $4$-carbon side chain (butyl group) attached to every other carbon atom. This corresponds to the polymerization of $1$-hexene $(CH_2=CH-CH_2-CH_2-CH_2-CH_3)$. The radical polymerization of $1$-hexene involves the opening of the double bond to form the polymer chain.
126
DifficultMCQ
The copolymer formed by addition polymerization of styrene and acrylonitrile in the presence of peroxide is
A
$[C(C_6H_5)(CH_3)-CH(CN)-CH_2]_n$
B
$[CH_2-CH(C_6H_5)-CH_2-CH(CN)]_n$
C
$[CH_2-CH(C_6H_5)-CH(CN)-CH_2]_n$
D
$[CH(C_6H_5)-CH_2-CH_2-CH(CN)]_n$

Solution

(B) . Styrene $(CH_2=CH-C_6H_5)$ and acrylonitrile $(CH_2=CH-CN)$ undergo addition polymerization in the presence of peroxide to form a copolymer.
The monomers link in a head-to-tail fashion,resulting in the following structure:
$n CH_2=CH(C_6H_5) + n CH_2=CH(CN) \xrightarrow{\text{Peroxide}} [CH_2-CH(C_6H_5)-CH_2-CH(CN)]_n$
127
MediumMCQ
Which of the following polymers is synthesized using a free radical polymerization technique?
A
Terylene
B
Melamine polymer
C
Nylon $6, 6$
D
Teflon

Solution

(D) Teflon (polytetrafluoroethene) is an addition polymer formed by the free radical polymerization of its monomer,tetrafluoroethene $(CF_2 = CF_2)$.
In contrast,Terylene,Melamine polymer,and Nylon-$6, 6$ are condensation polymers formed by the elimination of small molecules like water or alcohol.
128
EasyMCQ
Bakelite is obtained from phenol by reacting with
A
Acetal
B
$CH_3CHO$
C
$HCHO$
D
Chlorobenzene

Solution

(C) Bakelite is a thermosetting polymer formed by the condensation polymerization of phenol and formaldehyde $(HCHO)$ in the presence of an acid or base catalyst.
The reaction involves the formation of ortho- and para-hydroxybenzyl alcohol derivatives,which further undergo cross-linking to form the complex structure of Bakelite.
129
EasyMCQ
Which one of the following is a chain growth polymerisation?
A
Nucleic acid
B
Polystyrene
C
Protein
D
Starch

Solution

(B) Chain growth polymerization involves the addition of monomers to the active site of a growing polymer chain,typically through free radical,cationic,or anionic mechanisms.
$Polystyrene$ is formed by the addition polymerization of styrene monomers,which is a classic example of chain growth polymerization.
$Nucleic$ $acid$,$protein$,and $starch$ are natural polymers formed through step-growth (condensation) polymerization.
130
EasyMCQ
Bakelite is obtained from phenol by reacting it with
A
Acetaldehyde
B
Chlorobenzene
C
Formaldehyde
D
Acetamide

Solution

(C) Bakelite is a thermosetting phenol-formaldehyde resin.
It is obtained by the condensation polymerization of phenol and formaldehyde in the presence of an acid or base catalyst.
131
DifficultMCQ
The major product of the following reaction is:
Question diagram
A
Option A
B
Option B
C
Option C
D
Option D

Solution

(A) Step $1$: Hydrolysis of the starting material. The starting material is $4$-methoxyphenyl acetate. Treatment with $dil. \ HCl$ and heat causes hydrolysis of the ester group,yielding $4$-methoxyphenol.
Step $2$: Polymerization. The $4$-methoxyphenol is then reacted with oxalic acid $(COOH)_2$. This is a condensation polymerization reaction where the phenolic $-OH$ groups react with the carboxylic acid groups of oxalic acid to form a polyester linkage. The resulting polymer contains the $4$-methoxyphenyl unit linked via ester bonds.
132
DifficultMCQ
The polymer obtained from the following reaction is:
Question diagram
A
$[ -C(=O)-(CH_2)_4-NH- ]_n$
B
$[ -NH-C(=O)-(CH_2)_4-C(=O)-NH- ]_n$
C
$[ -O-(CH_2)_5-C(=O)- ]_n$
D
$[ -O-C(=O)-(CH_2)_4-O- ]_n$

Solution

(C) The starting material is $6$-aminohexanoic acid $(H_2N-(CH_2)_5-COOH)$.
$(i)$ Treatment with $NaNO_2/H_3O^+$ converts the amino group to a hydroxyl group,forming $6$-hydroxyhexanoic acid $(HO-(CH_2)_5-COOH)$.
(ii) Polymerization of $6$-hydroxyhexanoic acid via self-esterification results in the polyester polycaprolactone,which has the repeating unit $[ -O-(CH_2)_5-C(=O)- ]_n$.
133
DifficultMCQ
The homopolymer formed from $4-$hydroxybutanoic acid is:
A
$-[O-C(=O)-(CH_2)_3-O]_n-$
B
$-[C(=O)-(CH_2)_2-C(=O)]_n-$
C
$-[C(=O)-(CH_2)_2-C(=O)-O]_n-$
D
$-[C(=O)-(CH_2)_3-O]_n-$

Solution

(D) $4-$hydroxybutanoic acid $(HO-CH_2-CH_2-CH_2-COOH)$ undergoes self-condensation polymerization to form a polyester.
During this process,a water molecule is eliminated from each monomer unit.
The resulting repeating unit is $-[C(=O)-(CH_2)_3-O]_n-$.
134
MediumMCQ
The two monomers for the synthesis of Nylon $6, 6$ are
A
$HOOC(CH_2)_4COOH$ and $H_2N(CH_2)_6NH_2$
B
$HOOC(CH_2)_6COOH$ and $H_2N(CH_2)_6NH_2$
C
$HOOC(CH_2)_4COOH$ and $H_2N(CH_2)_4NH_2$
D
$HOOC(CH_2)_6COOH$ and $H_2N(CH_2)_4NH_2$

Solution

(A) Nylon $6, 6$ is a polyamide formed by the condensation polymerization of two monomers:
$1$. Adipic acid: $HOOC(CH_2)_4COOH$
$2$. Hexamethylene diamine: $H_2N(CH_2)_6NH_2$
Therefore,the correct option is $A$.
135
DifficultMCQ
The major product of the following reaction is:
Question diagram
A
$A$ polymer with a phenol group attached to the backbone.
B
$A$ polymer with a chlorine atom on the benzene ring and a methyl group on the backbone.
C
$A$ polymer with a chlorine atom on the benzene ring and no methyl group on the backbone.
D
$A$ polymer with a chlorine atom on the benzene ring and a methyl group on the backbone (different structure).

Solution

(B) Step $1$: Dehydrohalogenation of $1-(4-chlorophenyl)-2-chloropropane$ with alcoholic $KOH$ leads to the formation of $1-(4-chlorophenyl)prop-1-ene$ via an $E2$ elimination mechanism.
Step $2$: The resulting alkene,$1-(4-chlorophenyl)prop-1-ene$,undergoes free radical polymerization to form the corresponding polymer. The structure of the polymer is formed by the addition of the monomer units,resulting in a backbone with a methyl group and a $4-chlorophenyl$ substituent on adjacent carbons.
136
MediumMCQ
Which of the following is a condensation polymer?
A
Nylon $6,6$
B
Neoprene
C
Buna $-S$
D
Teflon

Solution

(A) Nylon $-6,6$ is a condensation polymer formed by the reaction between hexamethylene diamine and adipic acid with the elimination of water molecules.
Buna $-S$,Teflon,and Neoprene are examples of addition polymers.
137
EasyMCQ
Glyptal polymer is obtained from phthalic acid by treating it with
A
Malonic acid
B
Ethylene glycol
C
Maleic acid
D
Phenol

Solution

(B) Glyptal is a polyester formed by the condensation polymerization of ethylene glycol $(HO-CH_2-CH_2-OH)$ and phthalic acid $(C_6H_4(COOH)_2)$.
The reaction is as follows:
$n \ HO-CH_2-CH_2-OH + n \ C_6H_4(COOH)_2 \rightarrow \text{Glyptal} + 2n \ H_2O$
Thus,phthalic acid is treated with ethylene glycol to obtain glyptal.
138
EasyMCQ
Which of the following is a step-growth polymer?
A
Polyethylene
B
Polyester
C
Polypropylene
D
Polystyrene

Solution

(B) Step-growth polymerization involves the reaction of bifunctional or multifunctional monomers to form polymers with the elimination of small molecules like $H_2O$ or $CH_3OH$.
Polyesters,such as $Terylene$ (Dacron),are formed by the condensation polymerization of ethylene glycol and terephthalic acid,which is a classic example of step-growth polymerization.
Polyethylene,polypropylene,and polystyrene are addition polymers formed by chain-growth polymerization.
139
DifficultMCQ
How is a linear chain polymer formed?
A
By hydrolysis followed by condensation polymerization of $CH_3SiCl_3$
B
By hydrolysis of $(CH_3)_4Si$ through addition polymerization
C
By hydrolysis followed by condensation polymerization of $(CH_3)_2SiCl_2$
D
By hydrolysis followed by condensation polymerization of $(CH_3)_3SiCl$

Solution

(C) The hydrolysis of dialkyldichlorosilane $(R_2SiCl_2)$ produces dialkylsilanediol $(R_2Si(OH)_2)$.
These silanediol molecules undergo condensation polymerization to form linear chain silicone polymers.
For $(CH_3)_2SiCl_2$:
$n(CH_3)_2SiCl_2 + 2nH_2O \rightarrow n(CH_3)_2Si(OH)_2 + 2nHCl$
$n(CH_3)_2Si(OH)_2 \rightarrow -[O-Si(CH_3)_2-O]_n- + nH_2O$
Thus,$(CH_3)_2SiCl_2$ is the correct precursor for linear chain polymers.
140
MediumMCQ
What is the monomer unit of silicones?
A
$R_2SiCl_2$
B
$R_3SiCl$
C
$RSiCl_3$
D
$R_4Si$

Solution

(A) Silicones are synthetic organosilicon polymers with the general formula $(R_2SiO)_n$.
They are prepared by the hydrolysis of dialkyldichlorosilanes,$R_2SiCl_2$.
The hydrolysis of $R_2SiCl_2$ yields a dihydroxy derivative,$R_2Si(OH)_2$,which undergoes polymerization to form silicones.
Therefore,the monomer unit is $R_2SiCl_2$.
141
EasyMCQ
Bakelite is obtained from phenol by reacting with?
A
$CH_2OH-CH_2OH$
B
$CH_3-CHO$
C
$CH_3-CO-CH_3$
D
$HCHO$

Solution

(D) Bakelite is a thermosetting polymer formed by the condensation polymerization of phenol and formaldehyde $(HCHO)$ in the presence of an acid or base catalyst.
142
MediumMCQ
Which of the following products is a monomeric unit of Bakelite,formed in the Lederer-Manasse reaction?
A
o-Cresol
B
o-Hydroxybenzyl alcohol
C
Benzyl alcohol
D
Catechol

Solution

(B) The Lederer-Manasse reaction involves the reaction of phenol with formaldehyde in the presence of an acid or base catalyst.
This reaction leads to the formation of ortho- and para-hydroxybenzyl alcohols.
These hydroxybenzyl alcohols serve as the monomeric units for the polymerization process that produces Bakelite.
Among the given options,the structure corresponding to o-hydroxybenzyl alcohol is the correct monomeric unit.
143
MediumMCQ
$2-$chloro$-1,3-$butadiene is also known as
A
Chloroprene
B
Neoprene
C
Isoprene
D
Buna$-N$

Solution

(A) The chemical structure of $2-$chloro$-1,3-$butadiene is $CH_2=C(Cl)-CH=CH_2$.
This compound is commonly known as Chloroprene.
It is the monomer used for the preparation of the synthetic rubber known as Neoprene.
144
EasyMCQ
Teflon is a polymer of
A
Tetrafluoroethene
B
Tetrafluoroethane
C
Acrylonitrile
D
Caprolactam

Solution

(A) Teflon (polytetrafluoroethylene) is a polymer formed by the addition polymerization of tetrafluoroethene $(CF_2=CF_2)$ monomers.
It is an addition polymer.
145
EasyMCQ
The polymer formed by the condensation polymerization of ethylene glycol and phthalic acid is known as:
A
Glyptal
B
Bakelite
C
$PHBV$
D
$PVC$

Solution

(A) The condensation polymerization of ethylene glycol $(HO-CH_2-CH_2-OH)$ and phthalic acid $(C_6H_4(COOH)_2)$ results in the formation of a polyester known as Glyptal.
This is a cross-linked polymer used in the manufacture of paints and lacquers.
146
MediumMCQ
Monomers are converted to polymers by
A
Hydrolysis of monomer
B
Condensation between monomers
C
Combustion of monomers
D
Hydration of monomers

Solution

(B) Polymers are classified into two types based on the mode of polymerization: $Addition$ and $Condensation$ polymers.
$Condensation$ polymers are formed through a condensation reaction,where monomers join together and eliminate small molecules as by-products,such as $H_2O$ or $CH_3OH$.
An $Addition$ polymer is formed by the simple linking of monomers without the loss of any small molecules.
Therefore,monomers can be converted to polymers by a condensation reaction between monomers.
147
EasyMCQ
Ziegler-Natta catalyst is
A
$R_3Al$
B
$TiCl_4$
C
$R_3Al + TiCl_4$
D
$R_3B + TiCl_2$

Solution

(C) The Ziegler-Natta catalyst is a combination of an organometallic compound of a Group $1-3$ element (typically an alkyl aluminum compound like $R_3Al$) and a transition metal compound (typically a titanium compound like $TiCl_4$).
Thus,the correct composition is $R_3Al + TiCl_4$.
148
EasyMCQ
Which of the following is a step-growth polymer?
A
Bakelite
B
Polyethylene
C
Teflon
D
$PVC$

Solution

(A) Step-growth polymerization involves the reaction of bifunctional or multifunctional monomers to form polymers with the loss of small molecules like $H_2O$ or $HCl$.
Bakelite is a condensation polymer formed by the reaction of phenol and formaldehyde,which is a classic example of step-growth polymerization.
Polyethylene,Teflon,and $PVC$ are addition polymers formed by chain-growth polymerization.
149
EasyMCQ
An example of a condensation polymer is .............
A
$PVC$
B
Terylene
C
Polypropylene
D
Polystyrene

Solution

(B) Condensation polymers are formed by the repeated condensation reaction between two different bi-functional or tri-functional monomeric units,usually with the elimination of small molecules like $H_2O$,$HCl$,or $CH_3OH$.
$Terylene$ (also known as $Dacron$) is a condensation polymer formed by the polymerization of ethylene glycol and terephthalic acid.
$PVC$,$Polypropylene$,and $Polystyrene$ are all examples of addition polymers.

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