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Muscles Questions in English

Class 11 Biology · Locomotion and Movement · Muscles

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Showing 15 of 365 questions in English

351
MediumMCQ
Contraction of muscle fibre takes place by the sliding of $:-$
A
Thin filaments over the actin filaments
B
Thick filaments over the thin filaments
C
Thin filaments over the thick filaments
D
Thick filaments over the myosin filaments

Solution

(C) The mechanism of muscle contraction is explained by the Sliding Filament Theory.
According to this theory,muscle contraction occurs when thin filaments (actin) slide over the thick filaments (myosin).
This process is initiated by a signal sent by the central nervous system via a motor neuron.
As the thin filaments slide over the thick filaments,the $Z$-lines attached to the actin filaments are pulled inwards,causing the shortening of the sarcomere,which results in muscle contraction.
352
MediumMCQ
Given below are two statements $:-$
Statement-$I$ :- Each organised skeletal muscle in human body is made of a number of fascicles,held together by a common connective tissue layer called fascia.
Statement-$II$ :- The portion of the myofibril between two successive '$Z$' lines is considered as the functional unit of muscle contraction,known as a sarcomere.
In the light of the above statements,choose the correct answer from the options given below $:-$
A
Both statement-$I$ and statement-$II$ are true
B
Statement-$I$ is true but statement-$II$ is false
C
Statement-$I$ is false but statement-$II$ is true
D
Both statement-$I$ and statement-$II$ are false

Solution

(A) Statement-$I$ is true: In the human body,each organised skeletal muscle is composed of many muscle bundles or fascicles. These fascicles are held together by a common connective tissue layer called fascia.
Statement-$II$ is true: The portion of the myofibril between two successive '$Z$' lines is called a sarcomere. It is the functional unit of muscle contraction.
Therefore,both statements are correct.
353
MediumMCQ
Consider the following four statements $(a-d)$ and select the option which includes all the incorrect ones:
$(a)$ Skeletal muscle fibre is a syncytium as the sarcoplasm contains many nuclei.
$(b)$ In the centre of each $I$-band is an elastic fibre called $H$-line which bisects it.
$(c)$ In the resting state,a subunit of troponin masks the active binding sites for myosin on the actin filaments.
$(d)$ The contraction of a muscle fibre takes place by the sliding of the thick filaments over the thin filaments.
A
$(b), (c), (d)$
B
$(b), (d)$
C
$(a), (c)$
D
$(a), (c), (d)$

Solution

(B) Statement $(a)$ is correct: Skeletal muscle fibres are syncytial because the sarcoplasm contains many nuclei.
Statement $(b)$ is incorrect: In the centre of each $I$-band is an elastic fibre called the $Z$-line which bisects it,not the $H$-line.
Statement $(c)$ is correct: In the resting state,a subunit of troponin masks the active binding sites for myosin on the actin filaments.
Statement $(d)$ is incorrect: The contraction of a muscle fibre takes place by the sliding of the thin filaments over the thick filaments,not the other way around.
Therefore,the incorrect statements are $(b)$ and $(d)$.
354
EasyMCQ
The thick filaments in the '$A$' band are held together in the middle of this band by a thin fibrous membrane called $........$
A
$H$-line
B
$I$-line
C
$Z$-line
D
$M$-line

Solution

(D) In the structure of a muscle fiber (sarcomere),the '$A$' band contains thick filaments (myosin).
These thick filaments are held together in the central part of the '$A$' band by a thin fibrous membrane known as the '$M$-line' (or $M$-disk).
The '$H$-zone' is the central part of the '$A$' band where only thick filaments are present,while the '$M$-line' runs through the center of this '$H$-zone'.
355
MediumMCQ
Sarcoplasmic reticulum is present in which structure:
A
Muscle
B
Neuroglia
C
Nervous tissue
D
None

Solution

(A) The sarcoplasmic reticulum $(SR)$ is a specialized type of smooth endoplasmic reticulum found in smooth and striated muscle fibers. Its primary function is to store and release calcium ions $(Ca^{2+})$,which are essential for muscle contraction. Therefore,it is a characteristic structure of muscle cells.
356
MediumMCQ
During muscle contraction,$(P)$ get reduced whereas $(Q)$ retain the length. Here $P$ and $Q$ are $-$
A
$P-H$ bands,$Q-I$ bands
B
$P-M$ line,$Q-A$ bands
C
$P-I$ bands,$Q-A$ bands
D
$P-A$ bands,$Q-I$ bands

Solution

(C) According to the sliding filament theory of muscle contraction:
$(i)$ The $A$-bands (Anisotropic bands) retain their length because the length of myosin filaments remains constant.
$(ii)$ The $I$-bands (Isotropic bands) and the $H$-zone get reduced in length as the actin filaments slide over the myosin filaments towards the center of the sarcomere.
$(iii)$ Therefore,$(P)$ refers to $I$-bands (or $H$-zones) and $(Q)$ refers to $A$-bands. Given the options,$P$ is $I$-bands and $Q$ is $A$-bands.
357
MediumMCQ
$\text{ATP}$ase is located in $:-$
A
Actinin
B
Troponin
C
Myosin
D
Actin

Solution

(C) The enzyme $\text{ATP}$ase is present in the head of the myosin filament.
During muscle contraction,the myosin head binds to the active site on actin to form a cross-bridge.
This process requires energy,which is provided by the hydrolysis of $\text{ATP}$ catalyzed by the $\text{ATP}$ase enzyme located on the myosin head.
358
EasyMCQ
Given below are two statements:
$Statement-I$: Plasma creatinine is produced during catabolism of creatinine phosphate in skeletal muscle contraction.
$Statement-II$: Creatinine phosphate provides a ready source of high-energy phosphate.
In the light of the above two statements, choose the most appropriate answer from the options given below.
A
Both $Statement-I$ and $Statement-II$ are correct.
B
Both $Statement-I$ and $Statement-II$ are incorrect.
C
$Statement-I$ is correct but $Statement-II$ is incorrect.
D
$Statement-I$ is incorrect but $Statement-II$ is correct.

Solution

(D) $Statement-I$ is incorrect because plasma creatinine is produced by the non-enzymatic dehydration of creatine phosphate (or creatine) in muscles, not specifically during the catabolism of creatinine phosphate during contraction. Creatinine is a waste product.
$Statement-II$ is correct because creatine phosphate (phosphocreatine) acts as a rapid energy reserve in skeletal muscle, donating a phosphate group to $ADP$ to regenerate $ATP$ during intense muscle activity.
359
EasyMCQ
Proprioceptors are present in . . . . . . .
A
retina of eye and semi-circular canal.
B
joints,muscles and tendons.
C
taste buds,olfactory epithelium.
D
wall of venae cavae and carotid sinus

Solution

(B) Proprioceptors are specialized sensory receptors that provide information about the position,movement,and orientation of the body parts. They are primarily located in muscles,tendons,and joints,allowing the brain to sense the body's position in space (kinesthesia).
ReceptorsLocation
PhotoreceptorsRetina of Eye
StatoreceptorsInternal Ear (semicircular canals)
ChemoreceptorsTaste buds of tongue,Olfactory Epithelium of Nose
BaroreceptorsWall of venae cavae and carotid sinus
ProprioceptorsJoints,muscles and tendons
360
EasyMCQ
In the mechanism of muscle contraction or shortening of muscle,the . . . . . . get reduced whereas the . . . . . . retain the length.
A
$Z$ line,$I$ bands
B
$A$ bands,$Z$ line
C
$A$ bands,$I$ bands
D
$I$ bands,$A$ bands

Solution

(D) According to the sliding filament theory of muscle contraction,the thin filaments slide over the thick filaments.
During this process,the $I$ bands (isotropic bands) get reduced in length as the actin filaments move deeper into the $A$ bands.
Conversely,the $A$ bands (anisotropic bands) retain their original length because the myosin filaments do not change in size.
Therefore,the correct answer is $I$ bands,$A$ bands.
361
EasyMCQ
The functional unit of contraction is a
A
Portion of myofibril between two successive $Z$-lines
B
Portion of myofibril between two successive $M$-lines
C
Centre of the $H$-zone
D
Centre of the $I$-band

Solution

(A) The correct answer is $A$. The functional unit of muscle contraction is known as the $sarcomere$.
It is defined as the portion of a myofibril that lies between two successive $Z$-lines.
During muscle contraction,these $sarcomeres$ shorten as the actin and myosin filaments slide past each other.
362
EasyMCQ
Sarcomere is the functional unit of contraction in a muscle fibre. Identify the portion of myofibril that constitutes a sarcomere.
A
The portion of myofibril between two successive '$Z$' lines.
B
The portion of myofibril between two successive '$T$' bands.
C
The portion of myofibril between two successive '$A$' bands.
D
The portion of myofibril between two successive '$M$' lines.

Solution

(A) The correct answer is $A$.
$A$ sarcomere is defined as the functional unit of muscle contraction.
Structurally,it is the segment of a myofibril located between two successive '$Z$' lines (also known as '$Z$' discs).
These '$Z$' lines are elastic fibres that bisect the '$I$' bands and serve as the anchor points for actin filaments.
363
EasyMCQ
Identify the correct labels for the parts of the myosin monomer shown in the diagram.
Question diagram
A
$(A)$ Actin binding site,$(B)$ Head,$(C)$ $ATP$ binding site,$(D)$ Cross arm
B
$(A)$ Cross arm,$(B)$ Actin binding site,$(C)$ Head,$(D)$ $ATP$ binding site
C
$(A)$ $ATP$ binding site,$(B)$ Actin binding site,$(C)$ Head,$(D)$ Cross arm
D
$(A)$ Actin binding site,$(B)$ Head,$(C)$ $ATP$ binding site,$(D)$ Cross arm

Solution

(A) Based on the structure of the myosin monomer (meromyosin):
$A$ represents the Actin binding sites located on the head.
$B$ represents the Head (globular head).
$C$ represents the $ATP$ binding site located on the head.
$D$ represents the Cross arm (short arm connecting the head to the tail).
Therefore,the correct labeling is: $A$ = Actin binding site,$B$ = Head,$C$ = $ATP$ binding site,$D$ = Cross arm.
364
EasyMCQ
The diagram given below represents the structure of a striated muscle fiber. Label the parts $A, B, C, D, E$ and $F$.
Question diagram
A
$A$-Sarcoplasm,$B$-Nucleus,$C$-Sarcolemma,$D$-Myofibril,$E$-Dark band,$F$-Light band
B
$A$-Sarcoplasm,$B$-Light band,$C$-Myofibril,$D$-Sarcolemma,$E$-Nucleus,$F$-Dark band
C
$A$-Light band,$B$-Sarcoplasm,$C$-Myofibril,$D$-Sarcolemma,$E$-Nucleus,$F$-Dark band
D
$A$-Sarcolemma,$B$-Nucleus,$C$-Dark band,$D$-Light band,$E$-Sarcoplasm,$F$-Myofibril

Solution

(C) The correct answer is $C$.
In a striated muscle fiber,the parts are labeled as follows:
$A$ represents the Light band ($I$-band).
$B$ represents the Sarcoplasm (cytoplasm of the muscle cell).
$C$ represents the Myofibril (contractile unit).
$D$ represents the Sarcolemma (plasma membrane of the muscle fiber).
$E$ represents the Nucleus (located at the periphery).
$F$ represents the Dark band ($A$-band).
365
MediumMCQ
Choose the correct statements regarding muscle contraction. $A$. $A$ motor neuron carries a signal sent by the Central Nervous System $(CNS)$ to the sarcolemma of the muscle fibre. $B$. The neural signal generates an action potential which causes the release of $Ca^{++}$ into sarcoplasm. $C$. Increase in $Ca^{++}$ inactivates the actin for breaking cross bridges. $D$. Actin binds to the myosin head to form a cross bridge. $E$. Shortening of sarcomere takes place,by pulling actin filaments towards the centre of '$A$' band. Choose the correct answer from the options given below:
A
$(1)$ $A$ and $B$ only
B
$(2)$ $C$ and $E$ only
C
$(3)$ $C$ and $D$ only
D
$(4)$ $A$,$B$,$D$ and $E$ only

Solution

(D) The correct statements are $A, B, D,$ and $E$.
Statement $A$ is correct: $A$ motor neuron transmits a signal from the $CNS$ to the sarcolemma.
Statement $B$ is correct: The neural signal triggers an action potential,leading to the release of $Ca^{++}$ ions into the sarcoplasm.
Statement $C$ is incorrect: $Ca^{++}$ binds to troponin on the actin filament,which exposes the active sites on actin,thereby facilitating (not inactivating) the formation of cross-bridges.
Statement $D$ is correct: The exposed active sites on actin bind to the myosin head to form a cross-bridge.
Statement $E$ is correct: The myosin heads pull the actin filaments towards the center of the '$A$' band,causing the sarcomere to shorten.
Therefore,the correct sequence of events leads to the conclusion that $A, B, D,$ and $E$ are correct.

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