Write the following cubes in expanded form

$(3 x+2 y)^{3}$

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$=(3 x)^{3}+(2 y)^{3}+3(3 x)(2 y)(3 x+2 y)$

$=27 x^{3}+8 y^{3}+18 x y(3 x+2 y)$

$=27 x^{3}+8 y^{3}+54 x^{2} y+36 x y^{2}$

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