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(B) According to the Remainder Theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Here,$p(x) = x^{3} + x^{2} - 26x + 24$ a

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$0$

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(B) According to the Remainder Theorem,if a polynomial $p(x)$ is divided by $(x - a)$,the remainder is $p(a)$.Here,$p(x) = x^{3} + x^{2} - 26x + 24$ and the divisor is $x - 4$,so $a = 4$.To find the remainder,we calculate $p(4)$:$p(4) = (4)^{3} + (4)^{2} - 26(4) + 24$$p(4) = 64 + 16 - 104 + 24$$p(4) = 80 - 104 + 24$$p(4) = -24 + 24 = 0$.Therefore,the remainder is $0$.

With the help of the remainder theorem,find the remainder when the polynomial $p(x) = x^{3} + x^{2} - 26x + 24$ is divided by the divisor $x - 4$.

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