(A) Given the $n^{th}$ term of the sequence is $a_{n} = 2^{n}$.To find the first five terms,we substitute $n = 1, 2, 3, 4, 5$ into the formula:For $n

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(A) Given the $n^{th}$ term of the sequence is $a_{n} = 2^{n}$.To find the first five terms,we substitute $n = 1, 2, 3, 4, 5$ into the formula:For $n = 1$: $a_{1} = 2^{1} = 2$For $n = 2$: $a_{2} = 2^{2} = 4$For $n = 3$: $a_{3} = 2^{3} = 8$For $n = 4$: $a_{4} = 2^{4} = 16$For $n = 5$: $a_{5} = 2^{5} = 32$Thus,the first five terms are $2, 4, 8, 16, 32$.

Class 11 Mathematics Sequences and Series Geometric progression

Easy

Write the first five terms of the sequence whose $n^{th}$ term is $a_{n} = 2^{n}$.

A
$2, 4, 8, 16, 32$
B
$1, 2, 4, 8, 16$
C
$4, 8, 16, 32, 64$
D
$2, 4, 6, 8, 10$

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Geometric progression

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Write the first five terms of the sequence whose $n^{th}$ term is $a_{n} = 2^{n}$.

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