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(A) $(i)$ In the expression $\frac{\pi}{2} x^2 + x$,the term containing $x^2$ is $\frac{\pi}{2} x^2$. Therefore,the coefficient of $x^2$ is $\frac{\pi

Vedclass · Accepted Answer

$\frac{\pi}{2}$ and $0$

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(A) $(i)$ In the expression $\frac{\pi}{2} x^2 + x$,the term containing $x^2$ is $\frac{\pi}{2} x^2$. Therefore,the coefficient of $x^2$ is $\frac{\pi}{2}$.$(ii)$ In the expression $\sqrt{2} x - 1$,there is no $x^2$ term. We can write this expression as $\sqrt{2} x - 1 + 0 \cdot x^2$. Therefore,the coefficient of $x^2$ is $0$.

Write the coefficients of $x^2$ in each of the following:
$(i)$ $\frac{\pi}{2} x^2 + x$
$(ii)$ $\sqrt{2} x - 1$

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Write the coefficients of $x^2$ in each of the following:$(i)$ $\frac{\pi}{2} x^2 + x$$(ii)$ $\sqrt{2} x - 1$