Write the coefficients of x^2 in each of the | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) $(i)$ In the expression $\frac{\pi}{2} x^2 + x$,the term containing $x^2$ is $\frac{\pi}{2} x^2$. Therefore,the coefficient of $x^2$ is $\frac{\pi

Vedclass · Accepted Answer

$\frac{\pi}{2}$ and $0$

Vedclass · Answer

(A) $(i)$ In the expression $\frac{\pi}{2} x^2 + x$,the term containing $x^2$ is $\frac{\pi}{2} x^2$. Therefore,the coefficient of $x^2$ is $\frac{\pi}{2}$.$(ii)$ In the expression $\sqrt{2} x - 1$,there is no $x^2$ term. We can write this expression as $\sqrt{2} x - 1 + 0 \cdot x^2$. Therefore,the coefficient of $x^2$ is $0$.

Write the coefficients of $x^2$ in each of the following:
$(i)$ $\frac{\pi}{2} x^2 + x$
$(ii)$ $\sqrt{2} x - 1$

Similar Questions

Use suitable identities to find the products: $(x+4)(x+10)$

Find the zero of the polynomial: $p(x) = 3x - 2$.

Write the degree of each of the following polynomials:
$(i)$ $5x^3 + 4x^2 + 7x$
$(ii)$ $4 - y^2$

Evaluate the following product without multiplying directly: $103 \times 107$

Write the coefficients of $x^2$ in each of the following:
$(i)$ $2+x^2+x$
$(ii)$ $2-x^2+x^3$

Vedclass Test Series

Exam Paper Generator

Online Exam Module

Write the coefficients of $x^2$ in each of the following:$(i)$ $\frac{\pi}{2} x^2 + x$$(ii)$ $\sqrt{2} x - 1$