When acceleration and average acceleration are equal for moving object ?
When acceleration and average acceleration are equal for moving object ?
Similar Questions
In the $s-t$ equation $\left(s=10+20 t-5 t^2\right)$, match the following columns.
Colum $I$
Colum $II$
$(A)$ Distance travelled in $3\,s$
$(p)$ $-20$ units
$(B)$ Displacement in $1\,s$
$(q)$ $15$ units
$(C)$ Initial acceleration
$(r)$ $25$ units
$(D)$ Velocity at $4\,s$
$(s)$ $-10$ units
| Colum $I$ | Colum $II$ |
| $(A)$ Distance travelled in $3\,s$ | $(p)$ $-20$ units |
| $(B)$ Displacement in $1\,s$ | $(q)$ $15$ units |
| $(C)$ Initial acceleration | $(r)$ $25$ units |
| $(D)$ Velocity at $4\,s$ | $(s)$ $-10$ units |
The displacement of a particle as a function of time is shown in the figure. The figure shows that
The displacement of a particle after time $t$ is given by $x = \left( {k/{b^2}} \right)\left( {1 - {e^{ - bt}}} \right)$ where $b$ is a constant. What is the acceleration of the particle?
The displacement of a particle after time $t$ is given by $x = \left( {k/{b^2}} \right)\left( {1 - {e^{ - bt}}} \right)$ where $b$ is a constant. What is the acceleration of the particle?
Suggest a suitable physical situation for following graphs.
Suggest a suitable physical situation for following graphs.
A particle moving along $x-$axis has acceleration $f$, at time $t$ , given by $ f=f_0$$\left( {1 - \frac{t}{T}} \right)$, where $f_0$ and $T$ are constants. The particle at $t=0$ has zero velocity . In the time interval between $t=0$ and the instant when $f=0$ , the particle 's velocity $(v_x)$ is
- [AIPMT 2007]