The displacement of a particle as a function of time is shown in the figure. The figure shows that
- AThe particle starts with certain velocity but the motion is retarded and finally the particle stops
- BThe velocity of the particle is constant throughout
- CThe acceleration of the particle is constant throughout.
- DThe particle starts with constant velocity,then motion is accelerated and finally the particle moves with another constant velocity
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Similar Questions
The position-time graphs for two students $A$ and $B$ returning from the school to their homes are shown in the figure.
$(A)$ $A$ lives closer to the school.
$(B)$ $B$ lives closer to the school.
$(C)$ $A$ takes less time to reach home.
$(D)$ $A$ travels faster than $B$.
$(E)$ $B$ travels faster than $A$.
Choose the correct answer from the options given below:
$(A)$ $A$ lives closer to the school.
$(B)$ $B$ lives closer to the school.
$(C)$ $A$ takes less time to reach home.
$(D)$ $A$ travels faster than $B$.
$(E)$ $B$ travels faster than $A$.
Choose the correct answer from the options given below:
For the given displacement-time graph,what will the corresponding velocity-time graph look like?
Difficult
View SolutionMatch Column-$I$ with Column-$II$:
The displacement $x$ of a particle varies with time $t$ as $x = a e^{-\alpha t} + b e^{\beta t}$,where $a, b, \alpha, \text{and } \beta$ are positive constants. The velocity of the particle will:
DifficultAIPMT 2005
View Solution$A$ particle shows a distance-time curve as shown in the figure. The maximum instantaneous velocity of the particle is around the point:
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