The displacement of a particle after time $t$ is given by $x = \left( {k/{b^2}} \right)\left( {1 - {e^{ - bt}}} \right)$ where $b$ is a constant. What is the acceleration of the particle?
The displacement of a particle after time $t$ is given by $x = \left( {k/{b^2}} \right)\left( {1 - {e^{ - bt}}} \right)$ where $b$ is a constant. What is the acceleration of the particle?
- A
$k{e^{ - bt}}$
- B
$-k{e^{ - bt}}$
- C
$\frac{k}{{{b^2}}}{e^{ - bt}}$
- D
$\frac{-k}{{{b^2}}}{e^{ - bt}}$
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