Weight of 1 ,kg becomes 1/6 on moon. If radiu | vedclass

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Question

(d) ${g_m} = \frac{{G{M_m}}}{{R_m^2}}$ and ${g_m} = \frac{{{g_e}}}{6} = \frac{{9.8}}{6}\;m/{s^2}$$ = 1.63\;m/{s^2}$ 

Substituting ${R_m} = 1.7

Vedclass · Accepted Answer

$7.65 	imes {10^{22}}\,kg$

Vedclass · Answer

(d) ${g_m} = \frac{{G{M_m}}}{{R_m^2}}$ and ${g_m} = \frac{{{g_e}}}{6} = \frac{{9.8}}{6}\;m/{s^2}$$ = 1.63\;m/{s^2}$ 

Substituting ${R_m} = 1.768 	imes {10^6}m,$  ${g_m} = 1.63\;m/{s^2}$ and $G = 6.67 	imes {10^{ - 11}}N{m{ - }}{m^2}/k{g^2}$ 

We get ${M_m} = 7.65 	imes {10^{22}}kg$

Weight of $1 \,kg$ becomes $1/6$ on moon. If radius of moon is $1.768 \times {10^6}\,m$, then the mass of moon will be

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